3.129 \(\int x \sqrt{a+a \cosh (x)} \, dx\)

Optimal. Leaf size=32 \[ 2 x \tanh \left (\frac{x}{2}\right ) \sqrt{a \cosh (x)+a}-4 \sqrt{a \cosh (x)+a} \]

[Out]

-4*Sqrt[a + a*Cosh[x]] + 2*x*Sqrt[a + a*Cosh[x]]*Tanh[x/2]

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Rubi [A]  time = 0.0508111, antiderivative size = 32, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 12, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.25, Rules used = {3319, 3296, 2638} \[ 2 x \tanh \left (\frac{x}{2}\right ) \sqrt{a \cosh (x)+a}-4 \sqrt{a \cosh (x)+a} \]

Antiderivative was successfully verified.

[In]

Int[x*Sqrt[a + a*Cosh[x]],x]

[Out]

-4*Sqrt[a + a*Cosh[x]] + 2*x*Sqrt[a + a*Cosh[x]]*Tanh[x/2]

Rule 3319

Int[((c_.) + (d_.)*(x_))^(m_.)*((a_) + (b_.)*sin[(e_.) + (f_.)*(x_)])^(n_), x_Symbol] :> Dist[((2*a)^IntPart[n
]*(a + b*Sin[e + f*x])^FracPart[n])/Sin[e/2 + (a*Pi)/(4*b) + (f*x)/2]^(2*FracPart[n]), Int[(c + d*x)^m*Sin[e/2
+ (a*Pi)/(4*b) + (f*x)/2]^(2*n), x], x] /; FreeQ[{a, b, c, d, e, f, m}, x] && EqQ[a^2 - b^2, 0] && IntegerQ[n
+ 1/2] && (GtQ[n, 0] || IGtQ[m, 0])

Rule 3296

Int[((c_.) + (d_.)*(x_))^(m_.)*sin[(e_.) + (f_.)*(x_)], x_Symbol] :> -Simp[((c + d*x)^m*Cos[e + f*x])/f, x] +
Dist[(d*m)/f, Int[(c + d*x)^(m - 1)*Cos[e + f*x], x], x] /; FreeQ[{c, d, e, f}, x] && GtQ[m, 0]

Rule 2638

Int[sin[(c_.) + (d_.)*(x_)], x_Symbol] :> -Simp[Cos[c + d*x]/d, x] /; FreeQ[{c, d}, x]

Rubi steps

\begin{align*} \int x \sqrt{a+a \cosh (x)} \, dx &=\left (\sqrt{a+a \cosh (x)} \text{sech}\left (\frac{x}{2}\right )\right ) \int x \cosh \left (\frac{x}{2}\right ) \, dx\\ &=2 x \sqrt{a+a \cosh (x)} \tanh \left (\frac{x}{2}\right )-\left (2 \sqrt{a+a \cosh (x)} \text{sech}\left (\frac{x}{2}\right )\right ) \int \sinh \left (\frac{x}{2}\right ) \, dx\\ &=-4 \sqrt{a+a \cosh (x)}+2 x \sqrt{a+a \cosh (x)} \tanh \left (\frac{x}{2}\right )\\ \end{align*}

Mathematica [A]  time = 0.0201894, size = 22, normalized size = 0.69 \[ 2 \left (x \tanh \left (\frac{x}{2}\right )-2\right ) \sqrt{a (\cosh (x)+1)} \]

Antiderivative was successfully verified.

[In]

Integrate[x*Sqrt[a + a*Cosh[x]],x]

[Out]

2*Sqrt[a*(1 + Cosh[x])]*(-2 + x*Tanh[x/2])

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Maple [A]  time = 0.036, size = 38, normalized size = 1.2 \begin{align*}{\frac{\sqrt{2} \left ( x{{\rm e}^{x}}-x-2\,{{\rm e}^{x}}-2 \right ) }{{{\rm e}^{x}}+1}\sqrt{a \left ({{\rm e}^{x}}+1 \right ) ^{2}{{\rm e}^{-x}}}} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x*(a+a*cosh(x))^(1/2),x)

[Out]

2^(1/2)*(a*(exp(x)+1)^2*exp(-x))^(1/2)/(exp(x)+1)*(x*exp(x)-x-2*exp(x)-2)

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Maxima [A]  time = 1.68724, size = 59, normalized size = 1.84 \begin{align*} -{\left (\sqrt{2} \sqrt{a} x -{\left (\sqrt{2} \sqrt{a} x - 2 \, \sqrt{2} \sqrt{a}\right )} e^{x} + 2 \, \sqrt{2} \sqrt{a}\right )} e^{\left (-\frac{1}{2} \, x\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+a*cosh(x))^(1/2),x, algorithm="maxima")

[Out]

-(sqrt(2)*sqrt(a)*x - (sqrt(2)*sqrt(a)*x - 2*sqrt(2)*sqrt(a))*e^x + 2*sqrt(2)*sqrt(a))*e^(-1/2*x)

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Fricas [F(-2)]  time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: UnboundLocalError} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+a*cosh(x))^(1/2),x, algorithm="fricas")

[Out]

Exception raised: UnboundLocalError

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Sympy [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int x \sqrt{a \left (\cosh{\left (x \right )} + 1\right )}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+a*cosh(x))**(1/2),x)

[Out]

Integral(x*sqrt(a*(cosh(x) + 1)), x)

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \sqrt{a \cosh \left (x\right ) + a} x\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x*(a+a*cosh(x))^(1/2),x, algorithm="giac")

[Out]

integrate(sqrt(a*cosh(x) + a)*x, x)